Question

Perpendicular from the centre of a circle to a chord bisects the chord

Answer 1

this is the way you can solve

Answer 2

Given

in a circle c(o,r)

AB is a chord.

To prove :- AD = AB

PROVE:-

AO = OB (RADIUS)

angle ADO = angle OBD (each 90°)

OD =OD (common side)

hence,

∆AOF ~ BOD (SAS)

AD = BD

PROVED.