Perpendicular sides of a right angled triangle are 12 and 16 cm. What is the area of a semicircle drawn with the hypotenuse as the diameter?
(a) 314
(b) 154
(c) 616
(d) 100
Answers
Answered by
0
Answer:
50π=154cm²
Step-by-step explanation:
c²=b²+a²
12²+16²=c²
144+256=400=20²
therefore hypotenuse is 20cm
r=20/2=10cm
area of a semicircle is 1/2×3.14r²
=1/2×3.14×100=50×3.14=154cm²
Answered by
0
Answer:
Approx. 157.08
Step-by-step explanation:
hypotenuse=√12^2 + 16^2
=√144+256
=√400
=20
So, diameter of semicircle =20
Area =( πd^2)/8 or (πr^2)/2 = 157.08 approx.
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