Question

perpendicular to
1. In the given figure, PN and QM are both
PN = QM. PQ and MN bisect at X. Prove
that X is the midpoint of PG as well as MN.
line segment PQ. Also,​

Answer 1

Answer:

angleP=angleQ(A)

angle PXN=angleQXM(A)

PN=MQ(S)

BY AAS

PX = XQ

I hope my answer helps you☺☺

Answer 2

GIVEN

PN=QM

ANGLE P = ANGLE Q

WE TAKE : |_MPX = |_MQX

Step-by-step explanation:

NOW,

PN=QM

ANGLE P = ANGLE Q

|_MPX = |_MQX

(BY THE RULE OF SIDE ANGLE SIDE)

THEN, NX = MX (CPCT RULE)

SO, X IS THE MIDPOINT OF MN, PQ LINESEGMENT.

I HOPE IT WILL HELP YOU.