Question

person a completes a work w1 in 6 hours while person b completes another work w2 in 6 hours. if w1 is only equal to two-thirds of w2 then the number of hours required for a and b together to complete both w1 and w2 is:

Answer 1

W2=1

W1=2/3

Total work will be equal to : W1+W2=1+2/3=5/3

Work done by A in one hour=(2/3)/6=1/9

Work done by B in one hour=1/6

Now the total work done by A and B

1/9 +1/6=5/18

Number of hours required for A and B =(5/3)/(5/18)=6

Number of hours required for A and B together=6 hours