Math, asked by jakkeys, 1 year ago

Person A completes a work W1 in 6hours while person B completes another work W2 at 6hrs .If W1is only equal to two-thirds of W2 then the number of hours required for A and B together to complete both work

Answers

Answered by enyo
1

Suppose W2=1

So, according to the question:

W1=2/3

Total work i.e. W1+W2=1+2/3=5/3

Work done by A in one hour=(2/3)/6=1/9

Work done by B in one hour=1/6

Total work done by A and B together in one hour=1/9 +1/6=5/18

Number of hours required for A and B together=(5/3)/(5/18)=6

Therefore, Number of hours required for A and B together=6 hours


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