person A sold his car to person B at a profit of 20%and B sold it to C at a profit of 10%.person C sold it to mechanic at a loss of 9.09%.mechanic spent 10%of his purchasing price and then sold it at a profit of 8.33%to person A once again.what is the loss of person A??
Answers
Let the original price of the car be x
Person A sold his car to person B at a profit of 20%:
Profit = 20% of x = 0.2x
Selling Price = x + 0.2x = 1.2x
Person B sold it to Person C at a profit of 10%:
Profit = 10% of 1.2x = 0.1(1.2x) = 0.12x
Selling Price = 1.2x + 0.12x = 1.32x
Person C sold it to mechanic at a loss of 9.09%:
Loss = 9.09% of 1.32x = 0.0909(1.32x) = 0.119988x
Selling Price = 1.32x - 0.119988x = 1.200012x
Mechanic spent 10% of his purchasing price:
10% x 1.200012x = 0.1200012x
Total cost = 1.200012x + 0.1200012x = 1.3200132x
Mechanic sold it at a profit of 8.33%to person A :
profit = 8.33% x 1.3200132x = 0.0833 x 1.3200132x = 0.10996
Selling Price = 1.3200132x + 0.10996 = 1.43x
Calculate the loss:
Loss = 1.43x - x = 0.43x
Loss Percentage = (0.43x ÷ x ) x 100 = 43%
Answer: The loss is 43%
Answer:
Step-by-step explanation:
Person A sold his car to person B at a profit of 20%:
Profit = 20% of x = 0.2x
Selling Price = x + 0.2x = 1.2x
Person B sold it to Person C at a profit of 10%:
Profit = 10% of 1.2x = 0.1(1.2x) = 0.12x
Selling Price = 1.2x + 0.12x = 1.32x
Person C sold it to mechanic at a loss of 9.09%:
Loss = 9.09% of 1.32x = 0.0909(1.32x) = 0.119988x
Selling Price = 1.32x - 0.119988x = 1.200012x
Mechanic spent 10% of his purchasing price:
10% x 1.200012x = 0.1200012x
Total cost = 1.200012x + 0.1200012x = 1.3200132x
Mechanic sold it at a profit of 8.33%to person A :
profit = 8.33% x 1.3200132x = 0.0833 x 1.3200132x = 0.10996
Selling Price = 1.3200132x + 0.10996 = 1.43x
Calculate the loss:
Loss = 1.43x - x = 0.43x
Loss Percentage = (0.43x ÷ x ) x 100 = 43%
Answer: The loss is 43%