Person chooses a date at random in november for a party. find the probability that he chooses 1) a monday 2)wednesday 3)a friday 4) a saturday or a sunday
Answers
Step-by-step explanation:
Number of days in November = 30 days or 4 weeks and 2 days
Total outcomes = 30
Number of each day = 4
This means that there are surely at least 4 Monday Tuesday Wednesday........... and Sunday in November.
The remaining 2 days can be
1.) Monday Tuesday
2) Tuesday Wednesday
3) Wednesday Thursday
4) Thursday Friday
5) Friday Saturday
6) Saturday Sunday
7) Sunday Monday
Now,
Question 1)
Favourable outcomes = 4 guaranteed Monday + 1 either the 1st or 7th case
Probability of getting Monday from the 7 cases = 2/7
So
Probability of having the party on monday = 4+(2/7)/30
= 1/7
Question 2
Same goes for Wednesday.
P(E) = 1/7
Question 3
Also 1/7
Question 4
Favourable outcomes = 4 + (3/7)/30
= 31/210
0.1476
Sorry not much sure about this.
I'll update the Ques by evening if I find any mistake
hope this help