person was driving at 20 m/s he applied brakes which generated force equal to -500N find the distance after which the car will stop if it mass is 100kg
Answers
Answered by
3
Answer:
Given:
mass(m)=800kg
initial velocity (u)=20 m/s
final velocity (v) =0 m/s
distance(s)= 8m
We have to find acceleration which is the retardation.
2as = v square - u square
2a×8 = 0 square × 20 square
16a= - 400
a=-400/16
a= -25 m/s
Retarding force:
F=ma
F= 800 × (-25)
F= -20000N
Answered by
1
Answer:
Explanation:Given:
mass(m)=800kg
initial velocity (u)=20 m/s
final velocity (v) =0 m/s
distance(s)= 8m
We have to find acceleration which is the retardation.
2as = v square - u square
2a×8 = 0 square × 20 square
16a= - 400
a=-400/16
a= -25 m/s
Retarding force:
F=ma
F= 800 × (-25)
F= -20000N
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