Question

person with 100 kg mass is standing erect on the tip of both feet, as

shown in the figure of Exercise 6.3. Note that each foot is subject to the normal

force, equal to half of his or her weight. Find the contact force C exerted by the

bones, tibia and fibula, on the ankle joint, and the muscle force F on the tendon of

calcaneus at 37 with the horizontal. In this posture, the distance between the

application points of the contact force and the muscle force in a longitudinal cut

is 5 cm, and between the application points of the contact force and the normal

force, it is 6 cm.

37°

5 cm 6 cm

F​

Answer 1

Answer:

zk

Explanation:

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