Question

persons A and B of weight 60 kgwt and
40 kgwt respectively stand facing each
on a light rope stretched between them. Find
e ratio of distance covered by them when they
meet if their initial separation was 5 m.
​

Answer 1

Answer:

2m and 3m respectively.

Explanation:

Let distance covered by A is x

and distance covered by B is y

Using center of mass

M × x = m × y

60x = 40y

3x = 2y.........................equation 1

Also it is given that x + y = 5

&

From equation 1 x = 2y/3

therefore we get

• 2y/3 + y = 5
• 2y/3 + 3y/3 = 5
• 5y/3 = 5
• y = 3

and

• x = 2y/3 = 2

Answer 2

Answer:

3:2

Explanation:

because force is constant and acceleration is also constant so mass will be considered therefore 60:40 =2:3