Question

Pertineter and Area 2. Find the perimeter of the following res 3 30 tem 4 om 20 20 30 A cm 3 om 3 cm 5 em 2 cm (VIO 5 am (vii) 6 cm 6 cm 4 cm 50m 5 5 5 cm KO 2 om 7 cm 4 cm bom 2 om






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Answer 1

answer

Solution:

Solution:(a) Perimeter = Sum of all side

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cm

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cm

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cmPerimeter of fig(b) is 133 cm.

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cmPerimeter of fig(b) is 133 cm.(c) Perimeter = Sum of all side

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cmPerimeter of fig(b) is 133 cm.(c) Perimeter = Sum of all side= 15 + 15 + 15 + 15

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cmPerimeter of fig(b) is 133 cm.(c) Perimeter = Sum of all side= 15 + 15 + 15 + 15= 60 cm

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cmPerimeter of fig(b) is 133 cm.(c) Perimeter = Sum of all side= 15 + 15 + 15 + 15= 60 cmPerimeter of fig(c) is 60 cm.

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cmPerimeter of fig(b) is 133 cm.(c) Perimeter = Sum of all side= 15 + 15 + 15 + 15= 60 cmPerimeter of fig(c) is 60 cm.(d) Perimeter = Sum of all sides

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cmPerimeter of fig(b) is 133 cm.(c) Perimeter = Sum of all side= 15 + 15 + 15 + 15= 60 cmPerimeter of fig(c) is 60 cm.(d) Perimeter = Sum of all sides= 4 + 4 + 4 + 4 + 4

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cmPerimeter of fig(b) is 133 cm.(c) Perimeter = Sum of all side= 15 + 15 + 15 + 15= 60 cmPerimeter of fig(c) is 60 cm.(d) Perimeter = Sum of all sides= 4 + 4 + 4 + 4 + 4= 20 cm

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cmPerimeter of fig(b) is 133 cm.(c) Perimeter = Sum of all side= 15 + 15 + 15 + 15= 60 cmPerimeter of fig(c) is 60 cm.(d) Perimeter = Sum of all sides= 4 + 4 + 4 + 4 + 4= 20 cmPerimeter of fig(d) is 20 cm.

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cmPerimeter of fig(b) is 133 cm.(c) Perimeter = Sum of all side= 15 + 15 + 15 + 15= 60 cmPerimeter of fig(c) is 60 cm.(d) Perimeter = Sum of all sides= 4 + 4 + 4 + 4 + 4= 20 cmPerimeter of fig(d) is 20 cm.(e) Perimeter = Sum of all sides

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cmPerimeter of fig(b) is 133 cm.(c) Perimeter = Sum of all side= 15 + 15 + 15 + 15= 60 cmPerimeter of fig(c) is 60 cm.(d) Perimeter = Sum of all sides= 4 + 4 + 4 + 4 + 4= 20 cmPerimeter of fig(d) is 20 cm.(e) Perimeter = Sum of all sides= 2.5 + 2.5 + 0.5 + 0.5 + 4 + 4 + 1

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cmPerimeter of fig(b) is 133 cm.(c) Perimeter = Sum of all side= 15 + 15 + 15 + 15= 60 cmPerimeter of fig(c) is 60 cm.(d) Perimeter = Sum of all sides= 4 + 4 + 4 + 4 + 4= 20 cmPerimeter of fig(d) is 20 cm.(e) Perimeter = Sum of all sides= 2.5 + 2.5 + 0.5 + 0.5 + 4 + 4 + 1= 5 + 1 + 9

Solution:(a) Perimeter = Sum of all side= 4 + 2 + 1 + 5= 12 cmPerimeter of fig(a) is 12 cm(b) Perimeter = Sum of all side= 23 + 35 + 40 + 35= 133 cmPerimeter of fig(b) is 133 cm.(c) Perimeter = Sum of all side= 15 + 15 + 15 + 15= 60 cmPerimeter of fig(c) is 60 cm.(d) Perimeter = Sum of all sides= 4 + 4 + 4 + 4 + 4= 20 cmPerimeter of fig(d) is 20 cm.(e) Perimeter = Sum of all sides= 2.5 + 2.5 + 0.5 + 0.5 + 4 + 4 + 1= 5 + 1 + 9= 15 cm