Peter can cover a certain distance in 1 hr 24 min by covering two- third of the distance at 4 kmph and the rest at 5 kmph. find the the total distance.
Answers
Answer:
Let's imagine that the total distance is x kilometer.
Two thirds of the distance will be 2x/3, which is covered at 4 kilometer per hour
Thus remaining distance
= 1x - 2x/3
= 3x - 2x/3
= x/3
We know speed = distance/time
Time = distance/speed
Peter covers two thirds of the distance at 4 km/per hour and the rest at 5 km/per hour.
Peter can cover a certain distance in 1 hr. and 24 mins.
1 hour 24 minutes (24/60 hours) can be written as 1.40 hours
According to statement
(2x / 3) / 4 + (x / 3) / 5 = 1.40 hours
2x / 12 + x / 15 = 1.40 hours
x / 6 + x / 15 = 1.40 hours
7x / 30 = 1.40
Cross multiplication
7x = 30 × 1.40
7x = 42
x = 42 / 7
x = 6 kilometers
The total distance is 6 kilometers
Answer total distance is 6 kilometers.
Total Distance is 6 km if it takes 1 hr 24 min to cover 2/3 of stance at 4 kmph and remaining at 5 kmph
Given : Peter can cover a certain distance in 1 hr 24 min by covering two- third of the distance at 4 kmph and the rest at 5 kmph.
To find : the the total distance.
Solution:
Assume that Total Distance = 3D km
two- third of the distance = (2/3) 3D = 2D km
Speed = 4 kmph
Time = Distance / Speed
Time = 2D/4 = D/2 hrs
Remaining Distance = 3D - 2D = D km
Speed = 5 kmph
Time = Distance / Speed
Time = D/5 hrs
Total time = D/2 + D/5 hrs
= (5D + 2D)/10
= 7D/10 hrs
Time = 1 hr 24 mins
= 1 + 24/60
= 1 + 2/5
= 7/5 hrs
7D/10 = 7/5
=> D = 2
=> 3D = 3 * 2 = 6
Total Distance is 6 km
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