Question

Peter got 30% of the maximum marks in an examination and failed by10 marks. However, paul, who took the same examination, got 40% of the total marks and got 15 marks more than the pass mark. What was the pass mark in the examination?

Answer 1

peter got 30% of max marks =.3x

i.e (x*30/100)

but he failed by 10 marks,

therefore passing mark i.e y=.3x+10

now, paul got 40% of max mark=.4x

but he get 15 marks more than passing marks,

therefore passing mark i.e y= .4x-15

now from both the eqtns,

.4x-15=.3x+10

x=250 i.e max marks

therefore passsing marks(put value of x)

y=.4x-15=.3x+10= 85

Answer 2

The passing marks in the examination is 85.

Step-by-step explanation:

Consider the provided information.

Peter got 30% of the maximum marks in an examination and failed by 10 marks.

Let the Maximum marks is x.

30% of x + 10 = Pass marks

Paul, who took the same examination, got 40% of the total marks and got 15 marks more than the pass mark.

40% of x - 15 = Pass marks.

Equate both the equation.

30% of x + 10 = 40% of x - 15

$\dfrac{30}{100}\times x+ 10=\dfrac{40}{100}\times x-15$

$0.3 x+ 10=0.4x-15$

$25=0.1x$

$x=250$

Hence, the maximum marks are 250.

30% of 250 + 10 = Pass marks

0.3×250+10 = Pass marks

Pass marks = 85

Hence, the passing marks in the examination is 85.

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