Question

Peter has $4.80 in his piggy bank, consisting of dimes and quarters. If there are 33 coins in all, how many of each does he have?

Answer 1

Answer:

10 quarters and 23 dimes

Step-by-step explanation:

Hi,

We should know U.S currencies,

1 dime = 10 pennies

i quarter = 25 pennies

1 $ = 100 pennies.

Now,

let 'x' be the number of dimes

let 'y' be the number of quarters

Given total number of coins = 33

=> x + y = 33-------(*)

Also, given that Peter has $4.80 in total

=> 10x + 25y = 480 ( After converting into pennies)

=>2x + 5y = 96---(**)

Solving equations (*) and (**), we get

y = 10 and x =23.

Hope, it helped !

Answer 2

Answer:

23 dines and 10 quarters

Step-by-step explanation:

Define x:

Let x be the number of dimes

Number of quarters = (33 - x)

Solve x:

Total sum is $4.80 ( A dime = $0.10 and a quarter is $0.25)

0.1x + 0.25(33 - x) = 4.80

0.1x + 8.25 - 0.25x = 4.8

0.15x = 3.45

x = 23

Find the number of each coins:

Dimes = x = 23

Quarters = 33 - x = 33 - 23 = 10

Answer: There are 23 dimes and 10 quarters.