Question

Peter invested an amount of rs.12,000 at the rate of 10 p.C.P.A. Simple interest and another amount at the rate of 20 p.C.P.A. Simple interest.The total interest earned at the end of one year on the total amount invested became 14 p.C.P.A..Find the total amount invested.

Answer 1

Answer:

12000+8000=20000

Step-by-step explanation:

plz see the explained answer in given pic

Answer 2

Rs 20,000 would be invested.

Step-by-step explanation:

We know that,

Simple interest formula,

$I=\frac{P\times r\times t}{100}$

Where,

P = principal,

r = rate of interest,

t = number of periods,

If P = 12000, r = 10%, t = 1,

Simple interest would be,

$I_1=\frac{12000\times 10\times 1}{100}=\frac{120000}{100}=1200$

If r = 20%, t =1,

Simple interest would be,

$I_2=\frac{P\times 20\times 1}{100}=\frac{P}{5}$

If Principal = 12000 + P, r = 14%, t = 1,

$I=\frac{(12000+P)14}{100}$

According to the question,

$I=I_1+I_2$

$\frac{(12000+P)14}{100}=1200+\frac{P}{5}$

$\frac{168000+14P}{100}=\frac{6000+P}{5}$

$840000+70P=600000 + 100P$

$70P=600000 + 100P-840000$

$70P-100P=-240000$

$-30P=-240000$

$P=\frac{240000}{30}=8000$

Hence, the total amount invested = 12000 + 8000 = 20,000.

#Learn more :

Ganesh invested Rs 40,000 in a bank at 8 p.c.p.a. compound interest for 2 years. What would be difference in the interest earned if he invests the same amount for the same period but for simple interest at the same rate?

https://brainly.in/question/11763041