Peter is 5 years younger than Ashley. Four years later, Ashley will be twice as old as Peter. Find their present ages?
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Answer:
The present ages of Peter and Ashley are 1 and 6 years respectively.
Step-by-step explanation:
To solve these types of questions just form equations using the given pieces of information.
Let 'x' be the age of Peter and 'y' is the age of Ashley
Now form an equation from the given. That is,
⇒ x = y - 5 → (1)
It is also given that after 4 years, the age of Ashley will be twice the age of Peter. Therefore,
⇒ y + 4 = 2(x + 4) → (2)
Substitute equation (1) in (2) ⇒
y + 4 = 2(y - 5 + 4)
= 2(y - 1)
= 2y - 2
2y - y = 4 + 2
y = 6
Put the 'y' value in equation (1) ⇒
x = 6 - 5
x = 1
Hence the present ages of Peter and Ashley are 1 and 6 years respectively.
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