Question

Peter is playing snakes and ladder. He needs a six on first die and a four on other to win. The probability for Peter to win if first die already has a 6 is what,​

Answer 1

Answer:

Step-by-step explanation:

Since we already have a 6 on the first die, then we have to get a 4 on the next one.

Total outcomes = 6 {1,2,3,4,5,6}

Favourable outcomes = 1 {1}

Probability of getting a 4 on the second die and winning =  Favourable outcomes / Total outcomes = 1/6 (ANS)

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