Question

Peter reads 2/5 of a book on the first day and 5/6 of the remainder on the second day. If the number of pages still unread is 50, how many pages does the book contain?

Answer 1

Answer:

The answer is 500

500*2/5=200

500-200=300

300*5/6=250

Therfore the remaining pages are=300-250=50

Answer 2

Answer:

The number of pages the book contain = 500 pages

Step-by-step explanation:

Given Peter reads 2/5 of a book on first day

On second day reads 5/6 of the remainder of the book

And number of pages still unread is 50

Here we need to find total number of pages in book

Let X be the number of pages in book    

on first day peter reads 2/5 of the book = $\frac{2}{5} X$  

remaining pages after reading 2/5 of book = X $- \frac{2}{5} X$  

                                                                      =  $\frac{5X -2X}{5}$ = $\frac{3X}{5}$  

on second day Peter reads 5/6 of remainder part =  $\frac{5}{6} (\frac{3X}{5} )$=  $\frac{X}{2}$  

the total number of pages read by Peter =  $\frac{2}{5} X+ \frac{X}{2}$

                                                                    = $\frac{4X + 5X}{10}$ = $\frac{9X}{10}$  

from given data the number of pages still unread  = 50

⇒ The total number of pages =  numbers pages read + unread pages

                                           ⇒  X = $\frac{9X}{10} + 50$

                                           ⇒   X = $\frac{9X + 500}{10}$  

                                           ⇒ 10$X$ = 9X + 500

                                            ⇒ X = 500 pages

The number of pages the book contain = 500 pages