Question

Peter rolls 2 fair dice and adds the results from each.
Work out the probability of getting a total of 11.

Answer 1

Answer:

5+6=11

So,the probability to get 11 is 5+6

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Answer 2

The probability of getting a total of 11 is 1/18

Given :

Peter rolls 2 fair dice and adds the results from each.

To find :

The probability of getting a total of 11

Solution :

Step 1 of 3 :

Find total number of possible outcomes

Here it is given that a pair of dice has thrown once

So the event points are

= { (1,1), (1,2), (1,3), (1,4),(1,5),(1,6),(2,1), (2,2), (2,3), (2,4),(2,5),(2,6),(3,1), (3,2), (3,3), (3,4),(3,5),(3,6),(4,1), (4,2), (4,3), (4,4),(4,5),(4,6),(5,1), (5,2), (5,3), (5,4),(5,5),(5,6),(6,1), (6,2), (6,3), (6,4),(6,5),(6,6)}

So the total number of possible outcomes = 36

Step 2 of 3 :

Find total number of possible outcomes for the event

Let A be the event that of getting a total of 11

So the event points are (5,6) , (6,5)

So total number of possible outcomes for the event A is 2

Step 3 of 3 :

Find the probability

Hence the required probability

= P(A)

$\displaystyle \sf{ = \frac{Number \: of \: favourable \: cases \: to \: the \: event \: A }{Total \: number \: of \: possible \: outcomes }}$

$\displaystyle \sf{ = \frac{2}{36} }$

$\displaystyle \sf{ = \frac{1}{18} }$

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