Peter’s house is exactly 481m from school. To get home he walks
480m south and then he walks west. How far west does he have to walk?
Please answer step by step, urgent
Answers
Answer:
A TO B IS 480m Now B TO C we don't know. However, A TO C is 481m. Here angle B is 90°.
So simply applying Pythagoras theorem square of hypotenuse = square base + square of perpendicular
481^2= 480^2+ BC^2
BC^2= (481+480)(481-480) = 961
=> BC = sqrt 961= 31
He has to walk 31 meters west.
Given - Total distance and distance covered south
Find - Distance to be travelled on West
Solution - We are given the direct distance between house and school. Now, from school Peter walks south and then towards west. This will create a right angled triangle as shown in diagram. In the diagram, A to B shows South and B to C shows west.
So, finding the value of x using Pythagoras theorem.
Hypotenuse² = Perpendicular² + Base²
481² = 480² + x²
x² = 481² - 480²
We know : a² - b² = (a + b)(a - b).
x² = (481 + 480)(481 - 480)
x² = 961×1
x² = 961
x = ✓961
x = 31 meters
Hence, Peter has to walk 31 meters on West to reach his house.
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