Math, asked by asmaardar, 1 year ago

peter scored an average of 75 marks for two tests after 3rd test average increased to 81 how many marks did he get on the 3rd test

Answers

Answered by snehakshay16
0

Answer:

93

Step-by-step explanation:

Marks in first two tests= Average*2=75*2=150……[1]

Marks in all tests=Average in three tests*3=81*3=243……[2]

From 1 and 2

Third test marks=243-150=93

So,third test marks are 93

Answered by sharonr
0

Peter scored 93 marks in 3rd test

Solution:

The average is given as:

Average = \frac{ \text { sum of marks }}{ \text{ number of tests}}

Peter scored an average of 75 marks for two tests

Therefore,

75 = \frac{\text{ sum of two test marks}}{2}\\\\\text{ sum of two test marks} = 75 \times 2\\\\\text{ sum of two test marks} = 150

After 3rd test average increased to 81

81 = \frac{ \text{ sum of 3 test marks }} {3}\\\\\text{ sum of 3 test marks } = 81 \times 3\\\\\text{ sum of 3 test marks } = 243\\\\150 + third\ test\ mark = 243\\\\third\ test\ mark = 243 - 150\\\\third\ test\ mark = 93

Thus, he scored 93 in 3rd test

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