Math, asked by aditigupta85, 2 months ago

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Answered by sreeh123flyback
1

Step-by-step explanation:

 log_{2}( log_{3}( log_{4}(x) ) )  = 0 \\  log_{3}( log_{4}(x) )  =  {2}^{0} \\  log_{3}( log_{4}(x) )  = 1 \\   log_{4}(x)   =  {3}^{1}  \\  log_{4}(x)  = 3  \\  x = 4 {}^{3}  = 64 \\  log_{3}( log_{4}( log_{2}(y) ) )  = 0 \\  log_{4}( log_{2}(y) )  = 1 \\  log_{2}(y)  = 4 \\ y = 2 {}^{4}  = 16 \\  log_{4}( log_{2}( log_{3}(z) ) )  = 0 \\  log_{2}( log_{3}(z) )  = 1 \\  log_{3}(z)  = 2 \\ z =  {3}^{2}  = 9 \\ x + y + z = 64 + 16 + 9 = 89

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