pg 146 ncert class7 tey these question 5 full answer
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1.In triangle BAC and DAC,
I.Angle BAC=Angle DAC [because ray AZ bisects angle DAB]
II.Angle ACB=Angle ACD[because ray AZ also bisects angle
DCB]
III.Side AC=AC[Because AC is the common side]
2.Yes, triangle BAC is congruent to triangle DAC.[by AAS congruency rule]
3.Yes, AB=AD[C.P.C.T.]
4.Yes, here also CD=CB [C.P.C.T.]
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Answer:
(I)AB=AD [S.S.S]
<ADC=<ABC[A.A.A]
<ACD=<ABC[A.A.A]
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