Chemistry, asked by Shahnawaz3309, 1 year ago

PH of 0.000l in NaOH solution is

Answers

Answered by SAgogulnath

0

M = 1* 10power 4.

(OH) = log(oh)

log1*10power 4

ph of the solution is 4

Answered by umar87

0

log(NaOH)=log(0.0004)=

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