pH of 0.002M H2SO4
Please explain with proper explanation...
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pH is the negative logarithm of hydrogen concentration, which is written as:
-Log[H+]
Sulfuric acid (H2SO4) is a diprotic acid. This means that it donates two protons when dissociating in aqueous solution. The dissociation of diprotic acid in aqueous solution is a two-step reaction. Furthermore, each dissociation step has a distinctive Ka value. The first proton is a strong acid, thus it fully dissociate. On the other hand, the second proton is a weak acid, hence it partially dissociate. The dissociation of H2SO4 in water is as follows:
H2SO4 + H2O <——-> H+ (first proton) + HSO4-
HSO4- + H2O ←—...
Hope it helps you
-Log[H+]
Sulfuric acid (H2SO4) is a diprotic acid. This means that it donates two protons when dissociating in aqueous solution. The dissociation of diprotic acid in aqueous solution is a two-step reaction. Furthermore, each dissociation step has a distinctive Ka value. The first proton is a strong acid, thus it fully dissociate. On the other hand, the second proton is a weak acid, hence it partially dissociate. The dissociation of H2SO4 in water is as follows:
H2SO4 + H2O <——-> H+ (first proton) + HSO4-
HSO4- + H2O ←—...
Hope it helps you
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