PH of 0.005 H2SO4 will be?
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it wd be 0.005M I think
is a strong diprotic acid. The equation for ionization is
H2 SO 4 →2H +SO42 −
Each molecule of acid gives 2 molecules of H +
.The concentration of H + ion is 2 x 0.005 = 0.010M
pH=−log[H + ]=−log[0.01]=2.
pH=2
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