Question

) pH of 0.005M calcium acetate
(pka of CH3C00H - 4.74)
explain the method also​

Answer 1

Answer:

Final volume = 500+500500+500 mL = 1L

Concentration of Acetic Acid = molesvolume=0.5∗11=0.5molesvolume=0.5∗11=0.5 M

Concentration of Calcium Acetate = molesvolume=0.5∗0.51=0.25molesvolume=0.5∗0.51=0.25 M

So using Henderson equation:

pH=pKa+log0.25∗20.5=4.76

pH=pKa+log⁡0.25∗20.5=4.76

Rest is easy