Chemistry, asked by jayantgandate, 1 month ago

ph of 0.01 molar NaOH solution​

Answers

Answered by dharitrimohanty83
2

Answer:

NaOH (aq) is strong base solution

So, [OH-] = N = 10-²N

pOH = -log[OH-] = -log 10-² = 2

pH = 14 - pOH = 14 - 2

pH = 12 {Ans.}

Hope I help you

Answered by satyamdraugscpr
1

Answer:

PH =12 this is answered

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