ph of 0.01 molar NaOH solution
Answers
Answered by
2
Answer:
NaOH (aq) is strong base solution
So, [OH-] = N = 10-²N
pOH = -log[OH-] = -log 10-² = 2
pH = 14 - pOH = 14 - 2
pH = 12 {Ans.}
Hope I help you
Answered by
1
Answer:
PH =12 this is answered
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