Question

ph of 0.016 M naoh solution is

Answer 1

[OH]=0.016M

pOH=-log[OH]=-log(0.016)=1.79

pH+pOH=14

pH=14-pOH→14-1.79

pH=12.21

Answer 2

Answer:

pH=12.21

Explanation:

[OH]=0.016M

pOH=-log[OH]=-log(0.016)=1.79

pH+pOH=14

pH=14-pOH =14-1.79

pH=12.21

Hope it helps u

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