Question

ph of 0.1 M aqueous solution of a weak acid is 3 what is degree of dissociation​

Answer 1

Answer:

pH =3 = -log[H+]

[H+]= 1 x 10^ -3 M

[H+]= alpha x concentration

alpha= [H+] / concentration

1 x 10^-3/0.1

degree of dissociation= 1 x 10^-2.

Further

Ka~alpha^2 x concentration.

=(1x10^-2)^2 x 0.1

= 1x10^-5.