pH of 0.1M solution of a weak acid (HA) is 4.50. It is neutralized with NaOH solution to decrease the acid content to half. pH of the resulting solution is: (antilog of 0.5 = 3.162)
(a) 4.50 (b) 8.00 (c) 7.00 (d) 10.00
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Answer: a=28.458
b=50.592
c=44.286
d=63.24
Explanation: because if 0.5=3.162 what about 4.50 so it will be more if its more then you will have to multiply
4.50x3.162the divide by 0.5 and you will have to do this for each and every number the one that are given like 8.00.
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