ph of .01M of Naoh is?
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Let's assume the solution is0.1M. NaOH is a strong base, so this will produce 0.1mol/L of OH ions in solution. This will produce a pH of 13.
pOH = -log [1 × 10^-1]
= -log 1 + -log 10^-1
= 0 + -(-1) log 10
= 0 + 1 × 1
= 0 + 1
= 1
Now we know that ,
pH + pOH = 14
pH + 1 = 14
pH = 14 - 1
pH = 13
Therefore pH of 0.1 M NAOH solution is 13.
Hope you understood
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