Ph of 4.0 g/l naoh solution is
Answers
Answered by
2
Answer:
Moles of NaOH = 4g / (40 g/mol) = 0.1 mol
Molarity of NaOH = 0.1 mol / 1 Litre = 0.1 molar
[OH-] = 0.1
pOH = -log[OH-]
= - log(0.1)
= 1
pH = 14 - pOH
= 14 - 1
= 13
pH of given NaOH solution is 13
Similar questions