Question

pH of .5 N HCl at 298 K is

Answer 1

Answer: The pH of the given amount of HCl is 0.301

Explanation:

We are given:

Normality of HCl = 0.5 N

To calculate the molarity of the solution, we use the equation:

N = n × M

where,

N = normality of the solution

n = n -factor of HCl solution = 1

M = molarity of the solution

Putting values in above equation, we get:

$0.5=1\times M_{HCl}\\\\M_{HCl}=0.5M$

The chemical equation for the ionization of HCl is given as:

$HCl\rightleftharpoons H^++Cl^-$

           0.5    0.5

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

$[H^+]=0.5M$

Putting values in above equation, we get:

$pH=-\log(0.5)\\\\pH=0.301$

Hence, the pH of the given amount of HCl is 0.301