Question

pH of a HCl solution with 10^(-8) M

Answer 1

Just be careful when finding the value of [H+]

If there is no dissolved HCl ; pH of water is 7

which means that [H+] = 10^-7

with 6 x 10^-9 M HCl

[H+]
= ( 1 x 10^-7 ) + ( 6 x 10^-9 )
= ( 1.06 x 10^-7 )

pH = - log ( 1.06 x 10^-7 )
= - ( -7 + 0.0253 )
= 7 - 0.0253
= 6.9747 ___

Answer 2

Just be careful when finding the value of [H+]

if there is dissolved HCI ;pH of water is 7

which means that [H+]=10^ -7

with 6×10^-9M HCI

[H+]

=(1×10^-7)+(6×10^-9)

=(1.06×10^-7)

pH=-log(1.06×10^-7)

=-(-7+0.0253)

=6.9747__