Question

pH of a saturated solution of Ba(OH)2 is 12.Hence solubility product of Ba(OH)2 is.....

Answer 1

Ksp is 5*10^-9. { pOH = 4. [OH-] = 10^-4. [Ba+2] = 5*10^-5 }. Multiply their concentrations. If there is any any doubt, just let me know.