Question

pH of a saturated solution of Ca(oh)2 is 9.the solubility product of ca(oh)2 is:​

Answer 1

Answer:

$5 \times {10}^{ - 16}$

Explanation:

$ph = 9 \: hence \: poh = 5 \\ concentration \: of \: oh = 2s = {10}^{ - 5} \\ therefore \: s = 5 \times {10}^{ - 6} \\ ksp = 4 {s}^{3} \\ s = 4 ({5 \times {10}^{ - 6} })^{3} \\ 4 \times 125 \times {10}^{ - 18} \\ 5 \times {10}^{ - 16}$