Question

PH of dilutes solution of HCl is 6.95.Calculate molarity of the HCL solution.

Answer 1

We have, pH = -log  [H+]

so, [H+] = 10-pH 

Here, pH = 6.95

So, concentration  [H+]=  10-6.95 = 1.12 x 10-7 M

So, molarity of HCl solution is 1.12 x 10-7.

Answer 2

Given:

pH of HCl solution = 6.95

To find:

Molarity of HCl = ?

Formula to be used:

pH = -log$[H^+]$

Calculation:

As HCl is acid, it releases $H^+$ ions. Thus its concentration must be considered to the calculate the molarity of the solution.

∴ pH = -log$[H^+]$

$[H^+]$ = $10^{-pH}$

Thus substituting the given values in the following formula

$[H^+]$ = $10^{-pH}$

$[H^+]$ = $10^{-6.95}$

The standard value for $10^{-6.95}$ is equal to $11.22\times10^{-8}$.

$[H^+] = 1.12\times 10^{-7}$

Conclusion:

Thus the molarity of the HCl solution is calculated as $1.12\times 10^{-7}$.

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