Chemistry, asked by Ridhima7504, 1 year ago

Ph of solution at 25c which has twice as many hydroxide ion in pure water at 25c will be

Answers

Answered by IlaMends
138

Answer:The pH of the solution is 7.31.

Solution:

Hydroxide ion concentration in pure water at 25^oC :

K_w=1\times 10^{-14}=[OH^-][H^+]

Since, pH of water is neutral which means that [OH^-]=[H^+]

1\times 10^{-14}=[OH^-][OH^-]

[OH^-_{water}]=1\times 10^{-7}mol/L

The pH of solution at 25^oC which has twice as many hydroxide ion in pure water at 25^oC  will be:

[OH^-_{solution}]=2\times [OH^-_{water}]=2\times 10^{-7}mol/L

pOH=-log[OH^-_{solution}]=-log(2\times 10^{-7})=6.69

pH=14-pOH=14-6.69=7.31

The pH of the solution is 7.31.


Answered by Muskansai
3

Answer:

7.301

Explanation:

see attachment

Attachments:
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