Question

ph of the solution containing 0.2 M ch3cooh and 0.1M (ch3coo) 2Sr is (pKa of ch3cooh =4.7
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Answer 1

Answer:

4.7

Explanation:

Mixture of weak acid and its salt with strong base is acidic buffer

pH=pka + log[CH3COO-]

[CH3COOH]

[CH3COO-]=0.1*2=0.2M

[CH3COOH]=0.2M

pH=pka+ log0.2=4.7

0.2