Question

pH of the solution containing 4g of Naoh in 100 ml of soln
a)0
b)14
c)12
d)4​

Answer 1

Answer:

b) 14

Explanation:

Molar mass of NaOH= 40 gmol^-1

Then, no. of moles of NaOH in 4g, n = 4/40 = 0.1

Volume of soln, V = 100 ml = 0.1 L

Now,

[OH]- = n/V = 0.1/0.1 = 1

pOH = -log [OH]- = -log 1 = 0

We know,

pH + pOH = 14

So, pH = 14 - pOH = 14-0 = 14 (Ans)