Question

Ph of the solution having 500ml 0.1 m nh4oh + 250 ml 0.1 m hcl

Answer 1

Kb=[NH+4][OH−][NH4OH]=10−5

So 0.05[OH−]0.1=10−5

This assumes the ammonium ions formed from

NH4OH⇌NH+4+OH−

are negligible compared to those from the ammonium salt.

So [OH−]=2.10−5mol.dm−3

So pOH=4.7

So pH=14−4.7=9.3