PH value of 0.05 M H2So4
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given
H₂SO₄+2H₂O→2H₃O⁺+SO₄²⁻
0.5 2×0.5
pH=log(0.05M×2)
pH=log(0.1M)
pH=1
∴pH of 0.05M of H₂SO₄ is 1
H₂SO₄+2H₂O→2H₃O⁺+SO₄²⁻
0.5 2×0.5
pH=log(0.05M×2)
pH=log(0.1M)
pH=1
∴pH of 0.05M of H₂SO₄ is 1
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