pH value of 10 to the power -8
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(C) 6.96
Solution:
pH=-log[H+]
Here, [H+] from HCl=10^-8
and [H+] from water in which HCl is dissolved= 10^-7
so total [H+]=1.1×10^-7
Hence, pH=-log(1.1×10^-7)
=6.96
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