Phase relationship between the applied voltage and the current flowing through the inductive circuit is
Answers
Answer: The relation between current and voltage is
V = IR
Where V is the voltage
I is the electric current
R is the electrical resistance
Explanation :
Let us assume that the inductive wire has 2 ends A and B .
Now let us study about a concept in current electricity - Potential or Potential at a point
The potential at a point is the amount of work done in bringing a unit positive charge from infinity to that point .
Now different points have different potentials. Keeping this in mind , we can say that the ends A and B of the inductive wire have 2 different potentials .
Now the difference between the potentials of the points A and B is called the Potential Difference between the points A and B
Potential Difference is also called voltage.
Now a relation can be established between the voltage( potential difference) applied across the ends A and B of the inductive wire and the current flowing through it only by applying Ohm's Law of electrical resistance.
Now what is electrical resistance ?
Electrical Resistance is the obstruction offered to the electrical current flowing through the conductor( in this case inductive wire ) by the fixed atoms of the conductor .
Ohm's law of electrical resistance states that
Temperature and other physical conditions remaining constant , the electric current flowing through the conductor ( inductive wire ) is directly proportional to the potential difference or voltage applied across the ends the conductor( or wire ) .
Hence the Law states that -
Electric current I is directly proportional to voltage V
Or Electric current I = voltage V / electrical resistance R , where electrical resistance R is the constant of proportionality
Or I = V/R
Or V = IR , hence proved
Hope it helps :)