Math, asked by xoxogoon, 1 month ago

Pheeb was playing a treasure hunt. She reached her last clue. In the last leg of the hunt, she got a locked diary. She also got a note that said that to unlock the diary, she has to enter a number between 60 and 460, and it is an odd number. The clue also said that the numbers belong to the set: 0, 1, 2, 3, 4, 5. What will be the maximum number of trials that Pheeb has to take to unlock the lock of the diary?

Answers

Answered by amitnrw
0

Given :   a number between 60 and 460, and it is an odd number. The clue also said that the numbers belong to the set: 0, 1, 2, 3, 4, 5.

To Find :  Maximum  possible numbers

Solution:

Number between  60  to 460

Number is odd  

numbers belong to the set: 0, 1, 2, 3, 4, 5.

Hence unit digit must be  1  , 3  or  5

100 Digit  digit can be 1 , 2 , 3 , 4  

Tens Digit can be any of  0, 1, 2, 3, 4, 5.

if repetition of digits is allowed

Then  4 * 6 * 3     = 72  Possible numbers

72 trials required

if repetition of digits not allowed

when 100 Digit is  1 , 3 or  5   - 3 ways  then unit digit can be 2 ways

and 10's digit 4 ways

3 * 2 * 4 = 24

when 100 Digit is  2 or 4    - 2 ways  then unit digit can be 3 ways

and 10's digit 4 ways

2 * 3 * 4 = 24

Hence 48 trials required

repetition of digits is allowed  : 72 trials

repetition of digits not allowed  : 48 trials

Learn More:

If the maximum number of trials required to openall locks when there ...

https://brainly.in/question/11768517

Crack the co de numeric lock 189 147 964 523 286 - Brainly.in

brainly.in/question/16539564

Similar questions