Phil throws a ball upwards that weighs 55 Newtons (N). The ball travels at a speed of 4 meters per second (m/s) and reaches its maximum height at 9.5 meters (m). At what height is the potential energy of the ball equal to the kinetic energy of the ball? Round to the nearest hundredth if necessary.
Answers
Answer:4.75m
Explanation:
Its hard to explain.
Given : Phil throws a ball upwards that weighs 55 Newtons (N).
The ball travels at a speed of 4 meters per second (m/s) and reaches its maximum height at 9.5 meters (m).
To Find : At what height is the potential energy of the ball equal to the kinetic energy of the ball?
Solution:
TE = KE + PE
TE = Total Energy
KE = Kinetic Energy = (1/2) mv²
PE = Potential Energy = mgh
Phil throws a ball upwards that weighs 55 Newtons (N).
reaches its maximum height at 9.5 meters (m).
At max height v = 0
Hence KE = 0
PE = mgh
mg = 55N (weight)
h = 9.5
PE = 55 * 9.5 = 522.5 Joule
TE = PE + KE = 0 + 522.5 = 522.5 Joule
When PE = KE
=> PE = KE = TE/2
=> PE = 522.5/2
522.5/2 = 55 * h
=> h = 9.5/2
=> h = 4.75 m
At Height 4.75 m the potential energy of the ball equal to the kinetic energy of the ball
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