Phonesmart is having a sale on Bananas. If you buy one Bana11a at full price,
you get a second at half price. \tVhen couples come in to buy a pair of phones, sales
of Apricots and Bananas are equally likely.
Moreover, given that the first phone sold
is a Banana, the second phone is twice as
likely to be a Banana rather than an Apricot. What is the probability that a couple
buys a pair of Bananas?
Answers
Given : sales of Apricots and Bananas are equally likely.
Moreover, given that the first phone sold is a Banana, the second phone is twice as likely to be a Banana rather than an Apricot.
To Find : probability that a couple buys a pair of Bananas
Solution:
sales of Apricots and Bananas are equally likely.
P(B) = P(A) = 1/2
probability that a couple buys a pair of Bananas = 1st phone Banana and 2nd phone banana
P(B) = 1/2 for 1st Phone
As 1st phone is banana now the second phone is twice as likely to be a Banana rather than an Apricot.
Hence P(B) = 2/3 and P(A) = 1/3
probability that a couple buys a pair of Bananas = (1/2)(2/3) = 1/3
1/3 is the probability that a couple buys a pair of Bananas
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