Question

Phosphoric acid, H3PO4, is one of the main ingredients of soft drinks, detergents, and fertilizers. It can be
prepared with a series of reactions:
P4 + 502 → P4010

P4010 + 6H20 + 4H3PO4

Let us say we allow 1000 kg of
phosphorus to react with oxygen in a tank to yield 90% of tetraphosphorus decoxide (P4010). In the second step of the reaction, we react it with water to
yield 97% of H3PO4. How much in
kilogram of H3PO4 that was produced after series of reactions?
a. 1565.72 kg c. 2759.81 kg
b. 965.46 kg d. 2846.12 kg

( explanation and working needed)
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Answer 1

Answer:

What would you like to ask? ... We allow 62 g of phosphorus to react with excess oxygen which form ... This will help us to improve better .

Top answer

Moles of P4 = 62124 = 0.5 P4 + 5O2⟶ P4O10 0.5 moles Moles of P4O10 formed = 0.85 (yield) × 0.5 = 0.425 moles P4O10 + 6H2O⟶ H3PO4 0.425 moles Moles