Question

phosphorous 3 chloride is used in manufacturing of pesticides it is made by reacting phosphorous and chlorine
calculate the mass of PCL3 produced when 124 g of P4 was allowed to react with 213 g of chlorine
P4(s) + 6Cl2(g) = 4PCL3(l)​

Answer 1

Answer:

417.5

Explanation:

Moles P4 = 125 g / 123.8952 g/mol = 1.01

moles Cl2 = 323 g / 70.906 g/mol = 4.56

Moles Cl2 needed = 1.01 x 6 = 6.06

we have only 4.56 moles of Cl2 so it is the limiting reactant

moles PCl3 = 4.56 x 4 / 6 = 3.04

mass PCl3 = 3.04 mol x 137.3328 g/mol = 417.5 g